m(K) = 2.4 g
m(практ. K2SO4) = 4.6 g
W(выхода K2SO4) - ?n(K) = 2.4 g / 39 g / mol = 0.06 mol2K + H2SO4 = K2SO4 + H2
2n(K) = n(K2SO4) ; поэтому: n(K2SO4) = 0.06 mol / 2 = 0.03 mol ;
m(K2SO4 теоритич.) = 0.03 mol * 174 g / mol = 5.22 g
W(выхода K2SO4) = 4.6 g / 5.22 g = 0.8812 = 88.12%
Ответ: 88.12% .
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Answers & Comments
m(K) = 2.4 g
m(практ. K2SO4) = 4.6 g
W(выхода K2SO4) - ?
n(K) = 2.4 g / 39 g / mol = 0.06 mol
2K + H2SO4 = K2SO4 + H2
2n(K) = n(K2SO4) ; поэтому: n(K2SO4) = 0.06 mol / 2 = 0.03 mol ;
m(K2SO4 теоритич.) = 0.03 mol * 174 g / mol = 5.22 g
W(выхода K2SO4) = 4.6 g / 5.22 g = 0.8812 = 88.12%
Ответ: 88.12% .