-sin(П/2-arcctg(-1/4))=-cos(arcctg(-1/4))=cos(arcctg(1/4))=√17/17
cosx/√(1-cos^2x)=1/4
16cos^2x=1-cos^2x
cos^2x=1/17;
ответ 5)
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-sin(П/2-arcctg(-1/4))=-cos(arcctg(-1/4))=cos(arcctg(1/4))=√17/17
cosx/√(1-cos^2x)=1/4
16cos^2x=1-cos^2x
cos^2x=1/17;
ответ 5)