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shchipakinas
@shchipakinas
July 2022
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oganesbagoyan
Verified answer
1.
cosx = π/3 ;
не имеет решения
, т.к. π/3 ≈3,14 / 3 > 1 * * * -1 ≤ cosx ≤ 1 * * *
---
2.
(1/2) ^x
≥ 1/16
(1/2) ^x ≥ (1/2)
⁴ * * * 0 <1/2 <1 * * *
x ≤ 4 или иначе
x ∈ ( -∞ ; 4 ]
.
---
3.
16 ^ (Log(4) 5 =(4²) ^ (Log(4) 5 = 4 ^ (2Log(4) 5 = 4 ^ (Log(4) 5²) =
4^(Log(4) 25
=25.
---
4.
(
a) ^(3/4 ) *(a)^(1/2) ) = (a) ^(3/4 +1/2) =
(a) ^(5/4
)
.
---
5.
Loq(0,5) (3x-2) = -2 ;
Loq(1/2) (3x-2) = Loq(1/2) (1/2)⁻²
3x-2 = (1/2)⁻² ; * * * (1/2)⁻² = (2⁻¹)⁻² =2² =4 или (1/2)⁻² =1 / (1/2)² =1/(1/4) =4 *
3x -2 =4 ;
3x -2 =4 ;3x =6 ;
x = 2.
2 votes
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Answers & Comments
Verified answer
1.cosx = π/3 ;
не имеет решения , т.к. π/3 ≈3,14 / 3 > 1 * * * -1 ≤ cosx ≤ 1 * * *
---
2.
(1/2) ^x ≥ 1/16
(1/2) ^x ≥ (1/2)⁴ * * * 0 <1/2 <1 * * *
x ≤ 4 или иначе x ∈ ( -∞ ; 4 ].
---
3.
16 ^ (Log(4) 5 =(4²) ^ (Log(4) 5 = 4 ^ (2Log(4) 5 = 4 ^ (Log(4) 5²) =
4^(Log(4) 25 =25.
---
4.
(a) ^(3/4 ) *(a)^(1/2) ) = (a) ^(3/4 +1/2) = (a) ^(5/4) .
---
5.
Loq(0,5) (3x-2) = -2 ;
Loq(1/2) (3x-2) = Loq(1/2) (1/2)⁻²
3x-2 = (1/2)⁻² ; * * * (1/2)⁻² = (2⁻¹)⁻² =2² =4 или (1/2)⁻² =1 / (1/2)² =1/(1/4) =4 *
3x -2 =4 ;
3x -2 =4 ;3x =6 ;
x = 2.