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Ответ:

\left \{ {{x=0} \atop {y=1}} \right.

Объяснение:

\left \{ {{3^{x}+2^{x+y+1}-5=0} \atop {3^{x+1}-2^{x+y}-1=0}} \right.\left \{ {{3^{x}+2^{x+y}*2^{1}-5=0} \atop {3^{x}*3^{1}-2^{x+y}-1=0}} \right.

замена переменной:

3^{x}=a,\\2^{x+y}=b

a>0, b>0

получим систему уравнений относительно переменных a и b:

\left \{ {{a+2b-5=0} \atop {3a-b-1=0}|*2} \right. \left \{ {{a+2b-5=0} \atop {6a-2b-2=0}} \right. +

\left \{ {{a+2b-5=0} \atop {7a=7}} \right. \left \{ {{a+2b-5=0} \atop {a=1}} \right.\left \{ {{a=1} \atop {b=2}} \right.

обратная замена:

\left \{ {{3^{x}=1 } \atop {2^{x+y} =2}} \right. \left \{ {{3^{x}=3^{0}} \atop {2^{x+y}=2^{1}}} \right. \left \{ {{x=0} \atop {x+y=1}} \right. \left \{ {{x=0} \atop {y=1}} \right.

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