Ответ:
f'(x) = (2-x)'cosx + (2-x)(cosx)'=
-cosx- sinx(2-x)= = xsinx - 2sinx - cosx
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Ответ:
f'(x) = (2-x)'cosx + (2-x)(cosx)'=
-cosx- sinx(2-x)= = xsinx - 2sinx - cosx