(x + 19)(x - 3) - (2x - 1)(2x + 1) ≥ x - 38
x² + 19x - 3x - 57 - 4x² + 1 ≥ x - 38
-3x² + 15x - 18 ≥ 0
x² - 5x + 6 ≤ 0
D = 25 - 4*6 = 1
x1 = (5 + 1)/2 = 3
x2 = (5 - 1)/2 = 2
(x - 2)(x - 3) ≤ 0
Далее во вложении.
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Answers & Comments
(x + 19)(x - 3) - (2x - 1)(2x + 1) ≥ x - 38
x² + 19x - 3x - 57 - 4x² + 1 ≥ x - 38
-3x² + 15x - 18 ≥ 0
x² - 5x + 6 ≤ 0
D = 25 - 4*6 = 1
x1 = (5 + 1)/2 = 3
x2 = (5 - 1)/2 = 2
(x - 2)(x - 3) ≤ 0
Далее во вложении.