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Fecla
@Fecla
July 2022
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пожаалуйста!!!
решите неравенство
а) (2x−6)(x+6)>0
б)(33−x)(9+3x)≤0
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NeZeRAvix
Verified answer
А)
(2x-6)(x-6)>0
(2x-6)(x+6)=0
2x-6=0
2x=6
x=3
x+6=0
x=-6
+ -6 - 3 +
_______________°___________________°___________
x
Ответ: x∈(-∞;-6)U(3;+∞)
б)
(33-x)(9+3x)≤0
(33-x)(9+3x)=0
33-x=0
x=33
9+3x=0
3x=-9
x=-3
- + -
-3 33
______________________·______________________·_____________
x
Ответ: x∈(-∞;-3]U[33;+∞)
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Answers & Comments
Verified answer
А)(2x-6)(x-6)>0
(2x-6)(x+6)=0
2x-6=0
2x=6
x=3
x+6=0
x=-6
+ -6 - 3 +
_______________°___________________°___________
x
Ответ: x∈(-∞;-6)U(3;+∞)
б)
(33-x)(9+3x)≤0
(33-x)(9+3x)=0
33-x=0
x=33
9+3x=0
3x=-9
x=-3
- + -
-3 33
______________________·______________________·_____________
x
Ответ: x∈(-∞;-3]U[33;+∞)