Решите неравентсво
а) (x+1)(x−5)(x−11)<0
б) x(x−8)(x+6)>0
в) (x−4)(x−5)(x−7)(x−18)<0
а) (x+1)(x−5)(x−11)<0
б) x(x−8)(x+6)>0
в) (x−4)(x−5)(x−7)(x−18)<0
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(х+1)(х-5)=х²-5х+х-5=х²-4х-5
(х²-4х-5)(х-11)=х³-11х²-4х²+20х-5х+55=х³-15х²+15х<0
х³-15х²+15х=х(х²-15х+15)<0
х¹<0
х²-15х+15<0
D=15²-4*1*15=225-60=165
х²<15+√165/2
х³<15-√165/2
Ответ:х¹=0;х²=15+√165/2;х³=15-√165/2