дано

m(HCL)  = 7.3 g

----------------

m(NaCL)-?

NaCL+H2SO4-->NaHSO4+HCL

M(HCL) = 36,5 g/mol

n(HCL) = m/M = 7.3 / 36.5  = 0.2 mol

n(NaCL) = n(HCL) = 0.2 mol

M(NaCL) = 58,5 g/mol

m(NaCL) = n*M = 0.2*58.5 = 11.7 g

ответ 11.7  г