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Voronezh1999
@Voronezh1999
July 2021
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Пожалуйста, помогите 2 примера решить!
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oganesbagoyan
Verified answer
6/(x²-2x) -12/(x²+2x) =1/x;
6/x(x-2) -12/x(x+2) =1/x;
ОДЗ : x≠ -2 ; x ≠ 0 ;x ≠ 2 *** x≠ -2 ;0 ; 2 ***
6(x+2) -12(x-2)= (x-2)(x+2) ;
6x +12 -12x+24 =x² -4 ;
x² +6x -40 =0; **** D/4= 3² -(40) =9+40 =49 =7² ***
x = - 3 (+/-) √(3²+40)
x ₁= -3 -7= -10 ;
x₂ = -3 +7 = 4.
ответ :
-10 ; 4.
************************************************
x² +4x > 0 ;
x(x+4) >0 ;
----- " + " --------- ( -4) ------- " -" ---- --- 0 ----- "+" -----
ответ :
4) x < - 4 ; x > 0
1 votes
Thanks 1
Voronezh1999
Спасибо огромное))) 5 звезд вам ^_^
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Answers & Comments
Verified answer
6/(x²-2x) -12/(x²+2x) =1/x;6/x(x-2) -12/x(x+2) =1/x;
ОДЗ : x≠ -2 ; x ≠ 0 ;x ≠ 2 *** x≠ -2 ;0 ; 2 ***
6(x+2) -12(x-2)= (x-2)(x+2) ;
6x +12 -12x+24 =x² -4 ;
x² +6x -40 =0; **** D/4= 3² -(40) =9+40 =49 =7² ***
x = - 3 (+/-) √(3²+40)
x ₁= -3 -7= -10 ;
x₂ = -3 +7 = 4.
ответ : -10 ; 4.
************************************************
x² +4x > 0 ;
x(x+4) >0 ;
----- " + " --------- ( -4) ------- " -" ---- --- 0 ----- "+" -----
ответ : 4) x < - 4 ; x > 0