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Phoenix1997
@Phoenix1997
July 2022
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пожалуйста помогите как решить : tg(sinx)>0
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sedinalana
Tg (sin x) > 0
tg a > 0 a ∈ (πk; π/2+πk),k∈z
sin x ∈ [-1; 1]⇒sin x ∈ (0; 1]
x ∈ (2πk; π/2+2k],k∈z
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Answers & Comments
tg a > 0 a ∈ (πk; π/2+πk),k∈z
sin x ∈ [-1; 1]⇒sin x ∈ (0; 1]
x ∈ (2πk; π/2+2k],k∈z