Ответ:
Объяснение:
36 . y = x² + ∛( x² ) = x² + x^(2/3 ) ;
y' = ( x² + ∛( x² ) )' = 2x + 2/3 *x^(- 1/3 ) = 2x + 2/(3∛x ) .
37 . y = ∛x/( √x - 1 ) ;
y' = [∛x/( √x - 1 ) ]' = [ 1/3 *x^(- 2/3 )*(√x - 1 ) -∛x *( 1/2√x ) ]/( √x - 1 )² =
= [ (√x - 1 )/∛( x²) - ∛x/√x ]/( √x - 1 )² .
38 . y = ( x + √x )² ;
y' = [( x + √x )²]' = 2( x + √x ) *( x' + (√x )' ) = 2( x + √x )*( 1 + 1/( 2√x )) .
39 . y = ( x² - 1 )( x² + 1 ) = ( x² )² - 1² = x⁴ - 1 ;
y' = ( x⁴ - 1 )' = 4x³ - 0 = 4x³ .
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Answers & Comments
Ответ:
Объяснение:
36 . y = x² + ∛( x² ) = x² + x^(2/3 ) ;
y' = ( x² + ∛( x² ) )' = 2x + 2/3 *x^(- 1/3 ) = 2x + 2/(3∛x ) .
37 . y = ∛x/( √x - 1 ) ;
y' = [∛x/( √x - 1 ) ]' = [ 1/3 *x^(- 2/3 )*(√x - 1 ) -∛x *( 1/2√x ) ]/( √x - 1 )² =
= [ (√x - 1 )/∛( x²) - ∛x/√x ]/( √x - 1 )² .
38 . y = ( x + √x )² ;
y' = [( x + √x )²]' = 2( x + √x ) *( x' + (√x )' ) = 2( x + √x )*( 1 + 1/( 2√x )) .
39 . y = ( x² - 1 )( x² + 1 ) = ( x² )² - 1² = x⁴ - 1 ;
y' = ( x⁴ - 1 )' = 4x³ - 0 = 4x³ .