Ответ:
Пошаговое объяснение:
y' = ∫y''dx = ∫x²dx = x³/3 + c1 = x³/3 + 2
y = ∫y'dx = ∫(x³/3 + 2)dx = x⁴/12 + 2x + c2 = x⁴/12 + 2x
y(0) = 0
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Ответ:
Пошаговое объяснение:
y' = ∫y''dx = ∫x²dx = x³/3 + c1 = x³/3 + 2
y = ∫y'dx = ∫(x³/3 + 2)dx = x⁴/12 + 2x + c2 = x⁴/12 + 2x
y(0) = 0