Пожалуйста, помогите решить, буду благодарен ❤ Только напишите понятно((. Created by Denes169. geometriya-ru

№1. можно решить методом сложения:2x+y+y-2x=4+2; (2x и -2x взаимно уничтожаются)2y=6;y=3. Находим x: x+y=4;x+3=4;x=4-3=1. Ответ:(1;3)№2. {x-4y=3, | x (-1) (домножаем на минус один) > {-x+4y=-3Опять применяем сложение:-x+4y+x+y=4-3; (-x и x взаимно уничтожаются)5y=1;y=1/5=0,2. Находим x: x+y=4;x+0,2=4;x=4-0,2=3,8. Ответ:(3,8;0,2)№3. Сперва раскрываем скобки:1) {6x+18-12y+48=16-2x, 2) {10x-8=11-12+5yупрощаем:1) {6x-12y+2x=-18-48+16, 2) {10x-5y=8+11-121) {8x-12y=-50, 2) {10x-5y=7домножаем 1 уравнение на -5, 2 уравнение на 41) {-40x+60y=250, 2) 40x-20y=28Сложение:-40x+60y+40x-20y=250+28; (-40x и 40x взаимно уничтожаются)40y=278;y=6,95. Находим x: 10x-5y=7;10x-5 x 6,95=7;10x-34,75=7;10x=34,75+7;10x=41,75;x=4,175. Ответ:(4,175;6,95)Думаю, правильноСпасибо большоеВот только первый и второй номер, уравнением что ли писать?они все решаются уравнением, разница только в методе: графика, подстановка или сложение Новые вопросы в Геометрия10,11 очень срочно..Периметр ромба ABCD дорівнює 40 см. Відношення довжин його діагоналей AC:BD=Корень из 3 :1 , BK перпендикулярно AD. Серед чисел (А-Е) виберіть ті , як…і є значенням величин (1-4)1. АС. A.1202. Угол В. Б. 603. ВК. В.5 корень из 34. Площадь АВСD Г.10 корень из 3Д.50 корень из 3Е. 100 корень из 3ПОМОГИТЕ ПОЖАЛУЙСТА НУЖНО НА ЭКЗАМЕНЕ СРОЧНО!!!((СПОЧНО ЗАДАНИЯ НА ФОТОСРОЧНО ЗАДАНИЯ НА ФОТОВ треугольнике АВС угол С прямой, АВ = 7, cosA=0,3. Найдите АС.СРОЧНО!!!!!!! 1.В колі з центром в точці О діаметр АС та хорда АВ утворюють кут ВАС= 36*. Знайдіть кути трикутника ОВС.2. Накресліть тупокутний трику…тник МТН та побудуйте точку перетину медіан до сторін МТ і МН. Запишіть побудову.3.Побудуйте ГМТ рівновіддалених від сторін кута ∠А на відстані 5 см від вершини.Дві прямі перетинаються третьою за якої умови цій прямій є паралельними а відповідні кути рівні б будь-які два з утворених восьми кутів є рівними внут…рішні односторонні кути є рівними але не є прямими кутами г сума внутрішніх різносторонніх кутів дорівнює 190 срочно!!!!!!сфера з центром у точці D(2 -1 4) проходить через точку N(-1 2 3). за паралельного перенесення образом точки K(-2 6 -1) є точка M(-3 1 -4). складіть…рівняння сфери яка є оброзом сфери з центром у точці D у результаті цього паралельного перенесенняВ равнобедренной трапеции abcd стороны аd и bc являются основаниями. Основания равны 2 и 8. Боковые стороны ab и cd пересекаются в точке к. Найти п…лощадь треугольника bkc . Если высота трапеции 41. з точки а до площини альфа проведено похилу, проекція похилої на площину дорівнює 20 см. а відстань від точки а до площин 20 корінь з 3 см. знайдіт…ь довжину похилої.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере.КОМПАНИЯО насБлогКарьераУсловия пользованияАвторское правоПолитика конфиденциальностиПолитика использования файлов cookie Предпочтения cookie-файловСООБЩЕСТВОСообщество BrainlyBrainly для школ и учителейСообщество родителейКодекс честиПравила сообществаBrainly InsightsСтань помощникомПОМОЩЬЗарегистрируйсяЦентр помощиЦентр безопасностиДоговор о конфиденциальности полученной информацииУстанови приложение BrainlyСкачай iOS-приложениеСкачай для AndroidШкольные Знания.comPL: Brainly.plES: Brainly.latPT: Brainly.com.brFR: Nosdevoirs.frTR: Eodev.comRO: Brainly.roID: Brainly.co.idHI: Brainly.inPH: Brainly.phUS: Brainly.com (function() { window.jsData = window.jsData || {}; window.jsData.domain = 'znanija.com'; window.jsData.siteName = 'Школьные Знания.com'; window.jsData.dateFormat = 'd.m.Y'; window.jsData.footerConfig = {"socialMedia":[{"icon":"youtube","url":"https:\/\/www.youtube.com\/channel\/UCQ929YFR7IGeKlv-nXn-Qug?view_as=subscriber","ariaLabel":"youTube link"}],"company":[{"titleTranslationKey":"about_us_footer_link","url":"https:\/\/careers.brainly.com\/our-culture\/"},{"titleTranslationKey":"blog_footer_link","url":"https:\/\/blog.znanija.com"},{"titleTranslationKey":"careers_footer_link","url":"https:\/\/careers.brainly.com\/"},{"titleTranslationKey":"terms_of_use_footer_link","url":"https:\/\/znanija.com\/pages\/prawila","noHref":true},{"titleTranslationKey":"copyright_policy_footer_link","url":"https:\/\/znanija.com\/avtorskoe-pravo"},{"titleTranslationKey":"privacy_policy_footer_link","url":"https:\/\/znanija.com\/pages\/politika_konfidentsialnosti"},{"titleTranslationKey":"cookie_policy_footer_link","url":"https:\/\/znanija.com\/pages\/cookies_politika"},{"titleTranslationKey":"cookie_privacy_footer_link","handlerKey":"cookie_privacy_footer_link"}],"community":[{"titleTranslationKey":"brainly_community_footer_link","url":"https:\/\/znanija.com\/soobshestvo"},{"titleTranslationKey":"for_schools_teachers_footer_link","url":"https:\/\/znanija.com\/shkola-i-uchitelia"},{"titleTranslationKey":"brainly_for_parents_footer_link","url":"https:\/\/znanija.com\/roditeli"},{"titleTranslationKey":"honor_code_footer_link","url":"https:\/\/znanija.com\/kodeks-chesti"},{"titleTranslationKey":"community_guidelines_footer_link","url":"https:\/\/znanija.com\/pravila-soobshestva","noHref":true},{"titleTranslationKey":"brainly_insights_footer_link","url":"https:\/\/brainly.com\/insights"},{"titleTranslationKey":"become_a_volunteer_footer_link","url":"https:\/\/znanija.com\/volontery"}],"helpColumn":[{"titleTranslationKey":"signup_footer_link","url":"https:\/\/znanija.com\/signup?entry=1","noHref":true},{"titleTranslationKey":"help_center_footer_link","url":"https:\/\/faq.brainly.com\/hc\/ru"},{"titleTranslationKey":"safety_center_footer_link","url":"https:\/\/znanija.com\/centr-bezopasnosti"},{"titleTranslationKey":"responsible_disclosure_agreement_footer_link","url":"https:\/\/brainly.com\/responsible-disclosure-program"}]}; window.jsData.styleGuideAssets = { logo: { small: 'https://styleguide.znanija.com/images/logos/znanija-mobile-200611d052.svg', big: 'https://styleguide.znanija.com/images/logos/znanija-addd85e6f5.svg', plusSmall: 'https://styleguide.znanija.com/images/logos/znanija-plus-small-495ddebd8c.svg', plus: 'https://styleguide.znanija.com/images/logos/znanija-plus-337423fa26.svg' }, application_icons: { x180: 'https://styleguide.znanija.com/images/app-icons/znanija/180x180-1c0ebd78f4.png', } }; window.jsData.staticDomain = 'z-dn.net' window.jsData.currentStaticRelatedQuestionIds = [] window.jsData.displayAdsEnabled = false window.jsData.videoAdsEnabled = false window.jsData.deviceInformation = {"is_lowend":false,"user_agent":"iOS-App\/4.20.58 Brainly\/5395 CFNetwork\/1331.0.7 Darwin\/21.4.0"} window.jsData.newestQuestions = [{"id":49750338,"content":"10,11 \u043e\u0447\u0435\u043d\u044c \u0441\u0440\u043e\u0447\u043d\u043e.."},{"id":49750206,"content":"\u041f\u0435\u0440\u0438\u043c\u0435\u0442\u0440 \u0440\u043e\u043c\u0431\u0430 ABCD \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u0454 40 \u0441\u043c. \u0412\u0456\u0434\u043d\u043e\u0448\u0435\u043d\u043d\u044f \u0434\u043e\u0432\u0436\u0438\u043d \u0439\u043e\u0433\u043e \u0434\u0456\u0430\u0433\u043e\u043d\u0430\u043b\u0435\u0439 AC:BD=\u041a\u043e\u0440\u0435\u043d\u044c \u0438\u0437 3 :1 , BK \u043f\u0435\u0440\u043f\u0435\u043d\u0434\u0438\u043a\u0443\u043b\u044f\u0440\u043d\u043e AD. \u0421\u0435\u0440\u0435\u0434 \u0447\u0438\u0441\u0435\u043b (\u0410-\u0415) \u0432\u0438\u0431\u0435\u0440\u0456\u0442\u044c \u0442\u0456 , \u044f\u043a\u0456 \u0454 \u0437\u043d\u0430\u0447\u0435\u043d\u043d\u044f\u043c \u0432\u0435\u043b\u0438\u0447\u0438\u043d (1-4) \n1. \u0410\u0421. A.120\n2. \u0423\u0433\u043e\u043b \u0412. \u0411. 60\n3. \u0412\u041a. \u0412.5 \u043a\u043e\u0440\u0435\u043d\u044c \u0438\u0437 3\n4. \u041f\u043b\u043e\u0449\u0430\u0434\u044c \u0410\u0412\u0421D \u0413.10 \u043a\u043e\u0440\u0435\u043d\u044c \u0438\u0437 3\n \u0414.50 \u043a\u043e\u0440\u0435\u043d\u044c \u0438\u0437 3\n \u0415. 100 \u043a\u043e\u0440\u0435\u043d\u044c \u0438\u0437 3\n\u041f\u041e\u041c\u041e\u0413\u0418\u0422\u0415 \u041f\u041e\u0416\u0410\u041b\u0423\u0419\u0421\u0422\u0410 \u041d\u0423\u0416\u041d\u041e \u041d\u0410 \u042d\u041a\u0417\u0410\u041c\u0415\u041d\u0415 \u0421\u0420\u041e\u0427\u041d\u041e!!!(("},{"id":49749880,"content":"\u0421\u041f\u041e\u0427\u041d\u041e \u0417\u0410\u0414\u0410\u041d\u0418\u042f \u041d\u0410 \u0424\u041e\u0422\u041e\u200b"},{"id":49749879,"content":"\u0421\u0420\u041e\u0427\u041d\u041e \u0417\u0410\u0414\u0410\u041d\u0418\u042f \u041d\u0410 \u0424\u041e\u0422\u041e\u200b"},{"id":49749792,"content":"\u0412 \u0442\u0440\u0435\u0443\u0433\u043e\u043b\u044c\u043d\u0438\u043a\u0435 \u0410\u0412\u0421 \u0443\u0433\u043e\u043b \u0421 \u043f\u0440\u044f\u043c\u043e\u0439, \u0410\u0412 = 7, cosA=0,3. \u041d\u0430\u0439\u0434\u0438\u0442\u0435 \u0410\u0421.\u200b"},{"id":49749745,"content":"\u0421\u0420\u041e\u0427\u041d\u041e!!!!!!! 1.\u0412 \u043a\u043e\u043b\u0456 \u0437 \u0446\u0435\u043d\u0442\u0440\u043e\u043c \u0432 \u0442\u043e\u0447\u0446\u0456 \u041e \u0434\u0456\u0430\u043c\u0435\u0442\u0440 \u0410\u0421 \u0442\u0430 \u0445\u043e\u0440\u0434\u0430 \u0410\u0412 \u0443\u0442\u0432\u043e\u0440\u044e\u044e\u0442\u044c \u043a\u0443\u0442 \u0412\u0410\u0421= 36*. \u0417\u043d\u0430\u0439\u0434\u0456\u0442\u044c \u043a\u0443\u0442\u0438 \u0442\u0440\u0438\u043a\u0443\u0442\u043d\u0438\u043a\u0430 \u041e\u0412\u0421.\n2. \u041d\u0430\u043a\u0440\u0435\u0441\u043b\u0456\u0442\u044c \u0442\u0443\u043f\u043e\u043a\u0443\u0442\u043d\u0438\u0439 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Пожалуйста, помогите решить, буду благодарен ❤ Только напишите понятно((...

Denes169 @Denes169

June 2022 1 24 Report

Пожалуйста, помогите решить, буду благодарен ❤ Только напишите понятно((

Answers & Comments

mefoldium67 №1. можно решить методом сложения:
2x+y+y-2x=4+2; (2x и -2x взаимно уничтожаются)
2y=6;
y=3. Находим x: x+y=4;
x+3=4;
x=4-3=1. Ответ:(1;3)
№2. {x-4y=3, | x (-1) (домножаем на минус один) > {-x+4y=-3
Опять применяем сложение:
-x+4y+x+y=4-3; (-x и x взаимно уничтожаются)
5y=1;
y=1/5=0,2. Находим x: x+y=4;
x+0,2=4;
x=4-0,2=3,8. Ответ:(3,8;0,2)
№3. Сперва раскрываем скобки:
1) {6x+18-12y+48=16-2x, 2) {10x-8=11-12+5y
упрощаем:
1) {6x-12y+2x=-18-48+16, 2) {10x-5y=8+11-12
1) {8x-12y=-50, 2) {10x-5y=7
домножаем 1 уравнение на -5, 2 уравнение на 4
1) {-40x+60y=250, 2) 40x-20y=28
Сложение:
-40x+60y+40x-20y=250+28; (-40x и 40x взаимно уничтожаются)
40y=278;
y=6,95. Находим x: 10x-5y=7;
10x-5 x 6,95=7;
10x-34,75=7;
10x=34,75+7;
10x=41,75;
x=4,175. Ответ:(4,175;6,95)
Думаю, правильно

Спасибо большое
Вот только первый и второй номер, уравнением что ли писать?
они все решаются уравнением, разница только в методе: графика, подстановка или сложение