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pak6t
@pak6t
July 2022
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Пожалуйста, помогите с алгеброй
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sedinalana
|x|+|x+1|=1
1)x≤-1
-x-x-1=1
-2x=2
x=-1
2)-1<x<0
-x+x+1=1
1=1
x∈(-1;0)
3)x≥0
x+x+1=1
2x=0
x=0
x∈[-1;0]
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Answers & Comments
1)x≤-1
-x-x-1=1
-2x=2
x=-1
2)-1<x<0
-x+x+1=1
1=1
x∈(-1;0)
3)x≥0
x+x+1=1
2x=0
x=0
x∈[-1;0]