Дано: Решение
V(Al)=20 см3 n(Al)=0.02/22.4=0.00089 (моль)
m(Al)=m(Cu) m(Al)=0.00089•27=0.02403 (г)
V(Cu) —? m(Al)=m(Cu)=0.02403 г
n(Cu)=0.02403/64=0.000375 (моль)
V(Cu)=0.000375•22.4=0.0084 (дм3)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Дано: Решение
V(Al)=20 см3 n(Al)=0.02/22.4=0.00089 (моль)
m(Al)=m(Cu) m(Al)=0.00089•27=0.02403 (г)
V(Cu) —? m(Al)=m(Cu)=0.02403 г
n(Cu)=0.02403/64=0.000375 (моль)
V(Cu)=0.000375•22.4=0.0084 (дм3)