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Alyona122128
@Alyona122128
August 2022
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При каком значение х квадрат двучлена (4х-1) будет на 10 единиц больше квадрата двучлена ( 2х-3) , умноженного на 4?
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ptanyavamp
(4х-1)²-(2х-3)²*4=10
16х²-8х+1-(4х²-12х+9)*4=10
16х²-4х²-8х+12х+1-9=10
12х²+4х-8=10
12х²+4х=18
4х(3х+1)=18
3х+1=18:4х
3х+1=4,5х
3х-4,5х=-1
-1,5х=-1
х=2/3
4 votes
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Answers & Comments
16х²-8х+1-(4х²-12х+9)*4=10
16х²-4х²-8х+12х+1-9=10
12х²+4х-8=10
12х²+4х=18
4х(3х+1)=18
3х+1=18:4х
3х+1=4,5х
3х-4,5х=-1
-1,5х=-1
х=2/3