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dashasm06
@dashasm06
August 2022
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При каком значении b имеет один корень уравнение:
1) 2x²+4x-b=0;
2) 3x²-bx+12=0.
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andreq20024
Verified answer
1) D=0. 16 + 8b = 0. b= -2
2) D=0. b^2 - 144 = 0. b= ±12
4 votes
Thanks 4
ПрофиЗнания
Verified answer
1)
2x²+4x-b=0
D=16+8b=0
8b=-16
b=-2
2)
3x²-bx+12=0
D=b
²-144=0
b²=144
b=12 b=-12
2 votes
Thanks 5
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Answers & Comments
Verified answer
1) D=0. 16 + 8b = 0. b= -22) D=0. b^2 - 144 = 0. b= ±12
Verified answer
1) 2x²+4x-b=0D=16+8b=0
8b=-16
b=-2
2)3x²-bx+12=0
D=b²-144=0
b²=144
b=12 b=-12