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anastasiya315
@anastasiya315
July 2022
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При любых значениях Х и У верно неравенство 5х^2+4ху+у^2+6х>А. Найдите наибольшее возможное целое значение А
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yugolovin
Verified answer
Преобразуем правую часть:
(y^2+4yx+4x^2)+(x^2+6x+9)-9=
(y+2x)^2+(x+3)^2-9≥-9⇒A= - 10
Ответ: - 10
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Verified answer
Преобразуем правую часть:(y^2+4yx+4x^2)+(x^2+6x+9)-9=
(y+2x)^2+(x+3)^2-9≥-9⇒A= - 10
Ответ: - 10