Ответ:

Пошаговое объяснение:

1.4 . y = 4x⁵ + 5/x + 2/x⁴ - ∛x² = 4x⁵ + 5x⁻¹ + 2x⁻⁴ - x^(2/3) ;

 y ' = 4*5x⁴ - 1*5x⁻² - 2*(- 4 )x⁻⁵ -2/3 x^(-1/3) = 20x⁴ - 5/x² + 8/x⁵ - (2/3)/∛x .

2.4 .   y = tg⁶3x * cos4x² ;

 y ' = (tg⁶3x)' * cos4x²  + tg⁶3x *(cos4x² )' = 6tg⁵3x * (tg3x )' * cos4x² +

+ tg⁶3x *(- sin4x²) *(4x² )' =6tg⁵3x *cos4x² * 1/cos²3x * ( 3x )' - tg⁶3x * sin4x² X

X( 4 * 2x ) = ( 18tg⁵3x *cos4x²)/cos²3x - 8x tg⁶3x * sin4x² .