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ArtakN
@ArtakN
July 2022
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Производная, 60 баллов
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sedinalana
Verified answer
2
f`(x)=3x²+4x-5
f`(-1)=3-4-5=-6
3
f`(x)=e^x*sinx+e^x*cosx
f`(0)=1*sin0+1*cos0=1*0+1*1=1
4
f`(x)=(2x²-2x-x²-3)/(x-1)²=(x²-2x-3)/(x-1)²
f`(0)=-3/1=-3
5
1 votes
Thanks 1
ArtakN
2.b) почему -6? ведь 3×(-1)=-3
ArtakN
все, я понял
NaZaRiO24
......................
1 votes
Thanks 2
ArtakN
только где синус, вроде там же просто заменится на косинус.а?
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Answers & Comments
Verified answer
2f`(x)=3x²+4x-5
f`(-1)=3-4-5=-6
3
f`(x)=e^x*sinx+e^x*cosx
f`(0)=1*sin0+1*cos0=1*0+1*1=1
4
f`(x)=(2x²-2x-x²-3)/(x-1)²=(x²-2x-3)/(x-1)²
f`(0)=-3/1=-3
5