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virgi2016
@virgi2016
July 2022
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Прямая проходит через точки (3;0)и (0;4),имеет уравнение
1)3у=4х-12 2)3у=-4х+12 3)3у=-4х-12 4)3у=4х+12 5)х+у-4=0
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прр40
(3;0)и (0;4)
у=kx+l
3k+l=0
l=4
k= -4/3= -1*1/3
l=4
y= -1*1/3x+4. *3
3y=12-4x. -2)
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Answers & Comments
у=kx+l
3k+l=0
l=4
k= -4/3= -1*1/3
l=4
y= -1*1/3x+4. *3
3y=12-4x. -2)