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Kresai
@Kresai
June 2022
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Р(2:3) H(8:-5) К(3:1) М(-5:7) Найти вектор PH*KM и угол между этими векторами,помогите пожалуйста.
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victoriawildfox
PH = (8 - 2; -5 - 3)
= (6; -8)
KM = (
-5 - 3; 7 - 1)
= (-8; 6)
PH*KM = (6*(-8)+(-8)*6) = -48+(-48)=96
|PH| = √
6^2 + (-8)^2
= √36 + 64 = √100
= 10
|KM| = √
(-8)^2 + 6^2
= √64 + 36 = √100
=
10
cos угла между векторами =
PH*KM/|PH|*|KM| = 96/10*10 = 96/100 = 0,96
5 votes
Thanks 6
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Answers & Comments
KM = (-5 - 3; 7 - 1) = (-8; 6)
PH*KM = (6*(-8)+(-8)*6) = -48+(-48)=96
|PH| = √6^2 + (-8)^2 = √36 + 64 = √100 = 10
|KM| = √(-8)^2 + 6^2 = √64 + 36 = √100 = 10
cos угла между векторами = PH*KM/|PH|*|KM| = 96/10*10 = 96/100 = 0,96