Ответ:
дано
m(Na2CO3) = 53 g
m(HCL) = 73 g
----------------------
V(CO2) -?
M(Na2CO3) = 106 g/mol
M(HCL) =36,5 g/mol
n(Na2CO3) = m/M = 53 / 106 = 0.5 mol
n(HCL) = 73 / 36.5 =2 mol
n(Na2CO3) > n(HCL)
Na2CO3+2HCL-->2NaCL+H2O+CO2
n(Na2CO3) = n(CO2)
V(CO2) = n*Vm = 0.5 * 22.4 = 11.2 L
ответ 11.2 л
Объяснение:
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Answers & Comments
Ответ:
дано
m(Na2CO3) = 53 g
m(HCL) = 73 g
----------------------
V(CO2) -?
M(Na2CO3) = 106 g/mol
M(HCL) =36,5 g/mol
n(Na2CO3) = m/M = 53 / 106 = 0.5 mol
n(HCL) = 73 / 36.5 =2 mol
n(Na2CO3) > n(HCL)
Na2CO3+2HCL-->2NaCL+H2O+CO2
n(Na2CO3) = n(CO2)
V(CO2) = n*Vm = 0.5 * 22.4 = 11.2 L
ответ 11.2 л
Объяснение: