Разложить многочлен на множители:
x³ – 3x² - x
6a² – 2ab – 3ac + bc
a(b – c) + 3(c – b)
7c² – c – c³ + 7
(p² - 6) – q(p² - 6)²
x³ – 3x² - x
6a² – 2ab – 3ac + bc
a(b – c) + 3(c – b)
7c² – c – c³ + 7
(p² - 6) – q(p² - 6)²
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Ответ:
x(x^(2)-3x-1)
2a(3a-b)-c(3a-b)=(3a-b)(2a-c)
a(b-c)-3(b-c)=(b-c)(a-3)
7c^(2)+7-c-c^(3) = 7(c^(2)+1)-c(1+c^(2))=(c^(2)+1)(7-c)
(p^(2)-6)(p^(2)-6-q)