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leraloyko02
@leraloyko02
July 2022
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разложить на множители через дискриминант:
4x^2+11x-3
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Помощник98
D= 11^2-4*4*(-3)=169. X1= (-11+13)/8 =0.25 x2= (-11-13)/8= -3. По формуле
ax^2+bx+c=a(x-x1)(x-x2) получаем: 4x^2+11x-3= 4(x+3)(x-0,25)
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leraloyko02
Спасибо большое))
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Answers & Comments
ax^2+bx+c=a(x-x1)(x-x2) получаем: 4x^2+11x-3= 4(x+3)(x-0,25)