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mmalhanova
@mmalhanova
July 2022
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Разложить по множителям.
а²в-2в+ав²-2а=
х-в-3х²+3в²=
х²а-х²-ха+х³=
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n1982
а²в-2в+ав²-2а=ав(а+в)-2(в+а)=(а+в)(ав-2)
х-в-3х²+3в²=(х-в)-3(х
²-в²)=(х-в)(1-3(х+в))
х²а-х²-ха+х³=ха(х-1)-х
²(1-х)=(х-1)(-ха-х²)
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Answers & Comments
х-в-3х²+3в²=(х-в)-3(х²-в²)=(х-в)(1-3(х+в))
х²а-х²-ха+х³=ха(х-1)-х²(1-х)=(х-1)(-ха-х²)