Разложите на множетели:
1)-х^3+y^3
2)( n+3)^3-(n-3)^3
-х³+y³=у³-х³=(у-х)(у²+ху+х²) n+3)³-(n-3)³=(n+3-(n-3))((n+3)²+(n+3)(n-3)+(n-3)²)=6(n²+6n+9+n²-9+n²-6n+9)=6(3n²+9)=18(n²+3)
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Answers & Comments
-х³+y³=у³-х³=(у-х)(у²+ху+х²) n+3)³-(n-3)³=(n+3-(n-3))((n+3)²+(n+3)(n-3)+(n-3)²)=6(n²+6n+9+n²-9+n²-6n+9)=6(3n²+9)=18(n²+3)