Разложите на множетели 125-(2x-3)^3. Created by Nikirson4ik. algebra-ru

Разложите на множетели 125-(2x-3)^3...

Evgenia4836

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(5)³-(2x-3)³= (5-2x+3)*(25+5(2x-3)+(2x-3)²)= (8-2x)*(25+10x-15+4x²-12x+9)= (8-2x)*(4x²-2x+19)= 2*(4-x)*(4x²-2x+19)

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ax1lxa

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125 - (2x - 3)³ = (5 - (2x - 3)) * ((25 + 5(2x - 3) + (2x - 3)²) = (5 - 2x + 3) * (25 + 10x - 15 + 4x² - 12x + 9) = (8 - 2x) * (10 + 10x + 4x² - 12x + 9) = 2(4 - x) * (19 - 2x + 4x²)

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