разложите на множетели квадратный трёхчлен выделив квадрат двучлена
а)x^2-10x+24 б)9x^2-6x-3
а)x²-10x+24 = x²-10x+25 - 1 = (x²-10x+25) - 1 = (х-5)² - 1² = (х-5-1)*(х-5+1)=(х-6)*(х-4)
б)9x²-6x-3 = 9x²-6x+1-4 = (9x²-6x+1) - 4 = (3х-1)² - 2² = (3х-1-2)*(3х-1+2)=(3х-3)*(3х+1) = 3*(х-1)*(3х+1)
а)x^2-10x+24=(x-5)^2-1=(x-5-1)(x-5+1)=(x-6)(x-4)
б)9x^2-6x-3=3(3x^2-2x-1)=3*3(x-1)(x+1/3)=3(x-1)(3x+1)
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Answers & Comments
а)x²-10x+24 = x²-10x+25 - 1 = (x²-10x+25) - 1 = (х-5)² - 1² = (х-5-1)*(х-5+1)=(х-6)*(х-4)
б)9x²-6x-3 = 9x²-6x+1-4 = (9x²-6x+1) - 4 = (3х-1)² - 2² = (3х-1-2)*(3х-1+2)=(3х-3)*(3х+1) = 3*(х-1)*(3х+1)
а)x^2-10x+24=(x-5)^2-1=(x-5-1)(x-5+1)=(x-6)(x-4)
б)9x^2-6x-3=3(3x^2-2x-1)=3*3(x-1)(x+1/3)=3(x-1)(3x+1)