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rafaelkingz
@rafaelkingz
October 2021
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разложите на множители квадратный трехчлен x^2-x-20
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krugly1981
X² - x - 20 = 0
D = b² - 4ac = 1 - 4 × (-20) = 1 + 80 = 81= 9²
x1 = ( 1 + 9) / 2 = 5
x2 = ( 1 - 9)/2 = - 4
Разложим по формуле:
a( x - x1)( x - x2)
( x - 5)( x + 4)
8 votes
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Answers & Comments
D = b² - 4ac = 1 - 4 × (-20) = 1 + 80 = 81= 9²
x1 = ( 1 + 9) / 2 = 5
x2 = ( 1 - 9)/2 = - 4
Разложим по формуле:
a( x - x1)( x - x2)
( x - 5)( x + 4)