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NoahJane
@NoahJane
August 2022
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Разложите на множители с помощью группировки
(x-y)²+3·(y-x)
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TOR98
(x-y)^2-3(x-y)
(x-y)(x-y-3)
1 votes
Thanks 1
NoahJane
спасибо!
moboqe
(x-y)^2+3(y-x)=(y-x)(y-x)+3(y-x)=(y-x)(y-x+3)
2 votes
Thanks 1
NoahJane
спасибо!
TOR98
так это же не правильно
TOR98
(x-y)^2=x^2-2xy+y^2, а не (y-x)(x+y). последнее будет, если разложить (x^2-y^2)
moboqe
причём тут (х+у)?
moboqe
(x-y)^2=(y-x)^2
moboqe
(x-y)(x-y-3)= -(y-x)(x-y-3)=(y-x)(y-x+3)
TOR98
как ты разложил (x-y)^2?
moboqe
y^2-2xy+x^2
moboqe
(x-y)(x-y)
moboqe
(y-x)(y-x)
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(x-y)(x-y-3)