а) х² + 4ху + 4у²- 4 = (x + 2y)² - 2² = (x + 2y - 2)(x + 2y + 2)
б) х³ + у³+ 2x² - 2ху + 2у² = (x + y)(x² - xy + y²) + 2(x² - xy + y²) =
= (x + y + 2)(x² - xy + y²)
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а) х² + 4ху + 4у²- 4 = (x + 2y)² - 2² = (x + 2y - 2)(x + 2y + 2)
б) х³ + у³+ 2x² - 2ху + 2у² = (x + y)(x² - xy + y²) + 2(x² - xy + y²) =
= (x + y + 2)(x² - xy + y²)