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26Liza
@26Liza
November 2021
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Разложите на множители x3+7x2−3x−21
Помогите пж )))
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ВикаВикторовна
Verified answer
Х³+7х²-3х-21 = х²(х+7)-3(х+7) = (х+7)(х²-3)
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Answers & Comments
Verified answer
Х³+7х²-3х-21 = х²(х+7)-3(х+7) = (х+7)(х²-3)