1)
-1/8a²+1/4ab-1/8b² = -1/2(1/4a²-1/2ab+1/4b²)= -1/2(1/2a-1/2b)²
2)
3a(b-4)-2b+8 = 3a(b-4)-2(b-4) = (b-4)(3a-2)
3)
X³+3x²-x-3 = x²(x+3)-(x+3) = (x+3)(x²-1) = (x+3)(x-1)(x+1)
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Answers & Comments
1)
-1/8a²+1/4ab-1/8b² = -1/2(1/4a²-1/2ab+1/4b²)= -1/2(1/2a-1/2b)²
2)
3a(b-4)-2b+8 = 3a(b-4)-2(b-4) = (b-4)(3a-2)
3)
X³+3x²-x-3 = x²(x+3)-(x+3) = (x+3)(x²-1) = (x+3)(x-1)(x+1)