1)x^2+3x-40=(x+8)(x-5)
2) x^2+3x-40
D = b2 - 4ac = 32 - 4·1·(-40) = 9 + 160 = 169
x1=-3 - √169/2=-8
x2=-3 + √169/2=5
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1)x^2+3x-40=(x+8)(x-5)
2) x^2+3x-40
D = b2 - 4ac = 32 - 4·1·(-40) = 9 + 160 = 169
x1=-3 - √169/2=-8
x2=-3 + √169/2=5