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Dima3313
@Dima3313
February 2022
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Ребят, нужно подробное решение
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sedinalana
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2/(2+t)-1/t≤0
(2t-2-t)/[(2+t)t]≤0
(t-2)/[(2+t)t]≤0
t=2 t=-2 t=0
_ + _ +
-------------------(-2)------------(0)------------[2]-------------------
t<-2⇒log(7)(-x)<-2⇒-x<1/49⇒x>-1/49
0<t≤2⇒0<log(7)(-x)≤2⇒1<-x≤49⇒-49≤x<-1
Ответ x∈(-1/49;0)
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Answers & Comments
Verified answer
2/(2+t)-1/t≤0(2t-2-t)/[(2+t)t]≤0
(t-2)/[(2+t)t]≤0
t=2 t=-2 t=0
_ + _ +
-------------------(-2)------------(0)------------[2]-------------------
t<-2⇒log(7)(-x)<-2⇒-x<1/49⇒x>-1/49
0<t≤2⇒0<log(7)(-x)≤2⇒1<-x≤49⇒-49≤x<-1
Ответ x∈(-1/49;0)