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maslovae420
@maslovae420
August 2022
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РЕБЯТ ПОМОГИТЕ ПОЖАЛУЙСТА !!!!!!!!
3. Найдите корни уравнения: sin(4x)=cos(4x), принадлежащие отрезку [-1; 3].
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sedinalana
Verified answer
Разделим на сos4x
tg4x=1
4x=π/4+πn
x=π/16+πn/4,n∈z
x={-π/16;π/16;5π/16;9π/16;13π/16}
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Verified answer
Разделим на сos4xtg4x=1
4x=π/4+πn
x=π/16+πn/4,n∈z
x={-π/16;π/16;5π/16;9π/16;13π/16}