ребята,решите пожалуйста 1,2,5. Created by katerinka894. matematika-ru

№1.-5≤х-4≤9Можно записать с помощью системы уравнений:{x-4≥-5 {x-4≤9{x≥-5+4 ⇒x≥-1 ⇒ x∈[-1;∞){x≤9+4 ⇒x≤13 ⇒ x ∈ (-∞; 13]Объединим промежутки : х∈[-1;13]Ответ: 4) х∈[-1;13]№2.3√(10-2х) при х= -33√(10-2*(-3)) = 3√(10+6) = 3√16 = 3*4=12№5.х⁴+х²-20=0замена переменной:х²=tt²+t -20=0D= 1²-4*1*(-20) = 1+80=81=9²t₁= (-1-9)/ (2*1) = -10/2=-5t₂= (-1+9)/2 =8/2 = 4x²= -5 нет вещественных корнейх²=4х=√4х₁= 2х₂=-2 спасибки тебе огромное:* всегда пожалуйста) а можешь мне ещё помочь? Реклама Реклама Новые вопросы в Математика Разбейте на классы 43560001287 Назовите дроби со знаменателем 15 , которые больше 5\11,но меньше 6\11 Пожалуйста помогите!!! Помогите решить пожалуйста, нужно расписать примеры! Мальчик купил 5 кг хлеба. Может ли его покупка стоить 94 руб.? (цена за 1 кг — целое число) Помогите решить пожалуйста срочно!!! Помогите срочно решить! Основания трапеции равны 6 см и 16 см. Найдите отрезки, на которые диагональ трапеции делит среднюю линию. !!!!!! ПОЖАЛУЙСТА ПОМОГИТЕ СРОЧНО РЕШИТЬ!!!!!! Карточка по математике 6 классДаю 15 баллов за ответПомогите в 2 контейнерах было поровну яблок когда из первого контейнера взяли 13 кг яблок а из второго 31 кг то во втором контейнере осталось в 3 раза меньше я … блок чем в первом. Сколько килограммов яблок было в каждом контейнере в начале....... ПОЖАЛУЙСТА....... С решением........ в треугольнике авс найдите ас если ре=3.2см Предыдущий Следующий Реклама - это не так уж плохо Реклама - это не так уж плохо Понимаем - вы пришли сюда не за рекламой. Но она помогает нам предоставлять бесплатный доступ к Знаниям. Пожалуйста, внесите наш сайт в список разрешенных. ОК, разблокирую рекламу на Знаниях! Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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ребята,решите пожалуйста 1,2,5...

katerinka894 @katerinka894

September 2021 1 9 Report

ребята,решите пожалуйста 1,2,5

Answers & Comments

zhenyaM2002

Verified answer

№1.
-5≤х-4≤9
Можно записать с помощью системы уравнений:
{x-4≥-5
{x-4≤9

{x≥-5+4 ⇒x≥-1 ⇒ x∈[-1;∞)
{x≤9+4 ⇒x≤13 ⇒ x ∈ (-∞; 13]
Объединим промежутки : х∈[-1;13]

Ответ: 4) х∈[-1;13]

№2.
3√(10-2х) при х= -3
3√(10-2*(-3)) = 3√(10+6) = 3√16 = 3*4=12

№5.
х⁴+х²-20=0
замена переменной:
х²=t
t²+t -20=0
D= 1²-4*1*(-20) = 1+80=81=9²
t₁= (-1-9)/ (2*1) = -10/2=-5
t₂= (-1+9)/2 =8/2 = 4
x²= -5 нет вещественных корней
х²=4
х=√4
х₁= 2
х₂=-2