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katerinka894
@katerinka894
September 2021
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ребятки, помогите пожалуйста
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selmash21
1)
х=3-у
(3-у)^2+у^2=29
9-6у+у^2+у^2-29=0
2у^2-6у-20=0
у^2-3у-10=0
д=9-4×(-10)=49
у1=(3-7)/2=-2
у2=(3+7)/2=5
х1=3-(-2)=5
х2=3-5=-2
(5;-2)(-2;5)
2)
х=2+у
3(2+у)-у^2=6
6+3у-у^2-6=0
-у^2+3у=0
у(-у+3)=0
у1=0
-у+3=0
у2=3
х1=2+0=2
х2=2+3=5
(2;0)(5;3)
3)
{х+у=5
{ху=-14
х=5-у
у(5-у)=-14
5у-у^2+14=0
у^2-5у-14=0
д=25-4×(-14)=81
у1=(5-9)/2=-2
у2=(5+9)/2=7
х1=5-(-2)=7
х2=5-7=-2
(7;-2)(-2;7)
1 votes
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12Влада121
.................... 2)х=4 у=-2.
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Answers & Comments
х=3-у
(3-у)^2+у^2=29
9-6у+у^2+у^2-29=0
2у^2-6у-20=0
у^2-3у-10=0
д=9-4×(-10)=49
у1=(3-7)/2=-2
у2=(3+7)/2=5
х1=3-(-2)=5
х2=3-5=-2
(5;-2)(-2;5)
2)
х=2+у
3(2+у)-у^2=6
6+3у-у^2-6=0
-у^2+3у=0
у(-у+3)=0
у1=0
-у+3=0
у2=3
х1=2+0=2
х2=2+3=5
(2;0)(5;3)
3)
{х+у=5
{ху=-14
х=5-у
у(5-у)=-14
5у-у^2+14=0
у^2-5у-14=0
д=25-4×(-14)=81
у1=(5-9)/2=-2
у2=(5+9)/2=7
х1=5-(-2)=7
х2=5-7=-2
(7;-2)(-2;7)