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kaeru322
@kaeru322
August 2022
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решение пожалуйста
√7-㏒₂x² + ㏒₂x⁴ >4
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nKrynka
Решение
√7- ㏒₂x² + ㏒₂x⁴ > 4
ОДЗ: x > 0
√7- 2*㏒₂x + 4*㏒₂x > 4
2*㏒₂x > 4 - √7
㏒₂x > (4 -
√7)/2
x > 2^(4 -
√7)/2
2 votes
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Answers & Comments
√7- ㏒₂x² + ㏒₂x⁴ > 4
ОДЗ: x > 0
√7- 2*㏒₂x + 4*㏒₂x > 4
2*㏒₂x > 4 - √7
㏒₂x > (4 - √7)/2
x > 2^(4 - √7)/2