Решить 2х²-5х+2=0.................. Created by bulararsiniu. algebra-ru

Ответ:Ответ : 0,5 ; 2.

Решить 2х²-5х+2=0....................

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Ответ:

$2x {}^{2} - 5x + 2 = 0; \\ D = ( - 5) {}^{2} - 4*2*2 = 25 - 16 = 9 = 3 {}^{2} ; \\ x_{1} = \frac{5 - 3}{4} = \frac{2}{4} = \frac{1}{2} = 0,5; \\ x_{2} = \frac{5 + 3}{4} = \frac{8}{4} = 2.$

Ответ : 0,5 ; 2.

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kamilmatematik100504

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Ответ: $\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd\displaystyle\ \Large \boxed{\boldsymbol{x_1=2 \ ; \ x_2=\frac{1}{2}}}$

Объяснение: $\displaystyle\ \Large \boldsymbol{} 2x^2-5x+2=0 \\\\\\2x^2- \underbrace{ 4x-x}_{-5x}+2=0 \\\\\\ 2x^2-4x-x+2=0 \\\\2(x^2-2x)-(x-2)=0\\\\\\2x\underline{(x-2})-\underline{(x-2)}=0 \\\\\\(x-2)(2x-1)=0 \Longrightarrow x_1=2 \ ; \ x_2=\frac{1}{2}$

6 votes Thanks 5

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