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cet1999
@cet1999
July 2022
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решить методом гаусса систему уравнений 2х1 +х2 - х3 = 1
3х1 +2х2 - 2х3 =1
х1 - х2 + 2х3 = 5
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mozgachik
X₁=5+x₂-2x₃ (из 3-го ур-я);
2(5+x₂-2x₃)+x₂-x₃=10+2x₂-4x₃+x₂-x₃=10+3x₂-5x₃=1
x₂=5x₃/3-3,
x₁=5+5x₃/3-3-2x₃=2-x₃/3;
3(2-x₃/3)+2(5x₃/3-3)-2x₃=6-x₃+10x₃/3-6-2x₃=x₃/3=1
x₃=3;
Обратный ход:
x₂=5*3/3-3=2;
x₁=2-3/3=1.
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Answers & Comments
2(5+x₂-2x₃)+x₂-x₃=10+2x₂-4x₃+x₂-x₃=10+3x₂-5x₃=1
x₂=5x₃/3-3,
x₁=5+5x₃/3-3-2x₃=2-x₃/3;
3(2-x₃/3)+2(5x₃/3-3)-2x₃=6-x₃+10x₃/3-6-2x₃=x₃/3=1
x₃=3;
Обратный ход:
x₂=5*3/3-3=2;
x₁=2-3/3=1.