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AlexandraRen
@AlexandraRen
July 2022
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Решить неравенства:
1. 3x+4<0
2. x^2-2x-8≥0
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Armenia2780
1)3x+4<0
3x<-4
x<-4/3
x€(-oo;-4/3)
2)x²-2x-8≥0
D=(-2)²-4*(-8)=4+32=36=6²
x=(2±6)/2
x1=4;x2=-2
x²-2x-8=(x+2)(x-4)≥0
_+__-2___-___4__+___
x€(-oo;-2]U[4;+oo)
1 votes
Thanks 1
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Answers & Comments
3x<-4
x<-4/3
x€(-oo;-4/3)
2)x²-2x-8≥0
D=(-2)²-4*(-8)=4+32=36=6²
x=(2±6)/2
x1=4;x2=-2
x²-2x-8=(x+2)(x-4)≥0
_+__-2___-___4__+___
x€(-oo;-2]U[4;+oo)