Ответ:
Пошаговое объяснение:
№2
a) 6-3y+18x-9xy =3(2-y+6x-3xy) =3((-1-3x)y+(2+6x)) = 3((1+3x)(-1)y+(1+3x)2) = =3((1+3x)((-1)y+2)) =
3((1+3x)(-y+2)) =3(1+3x)(-y+2)
б) a^2-4a+4-p^2=-p^2+a^2-4a+4=(-p^2)+(a^2-4a+4)=-p^2+(a-2)^2=(a-2)^2-p^2= =(a-p-2)((a-2)+p) =(a-p-2)(a-2+p)
в) b^2+b+c-c^2=(b^2-c^2)+(b+c) =(b-c)(b+c)+1(b+c) =(b-c+1)(b+c)
№3
3y^3-12y^2=0
y^3-4y^2=0
y^2(y-4)=0
y^2=0 или y-4=0
y=0 y=4
Ответ: y=0; y=4
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Answers & Comments
Ответ:
Пошаговое объяснение:
№2
a) 6-3y+18x-9xy =3(2-y+6x-3xy) =3((-1-3x)y+(2+6x)) = 3((1+3x)(-1)y+(1+3x)2) = =3((1+3x)((-1)y+2)) =
3((1+3x)(-y+2)) =3(1+3x)(-y+2)
б) a^2-4a+4-p^2=-p^2+a^2-4a+4=(-p^2)+(a^2-4a+4)=-p^2+(a-2)^2=(a-2)^2-p^2= =(a-p-2)((a-2)+p) =(a-p-2)(a-2+p)
в) b^2+b+c-c^2=(b^2-c^2)+(b+c) =(b-c)(b+c)+1(b+c) =(b-c+1)(b+c)
№3
3y^3-12y^2=0
y^3-4y^2=0
y^2(y-4)=0
y^2=0 или y-4=0
y=0 y=4
Ответ: y=0; y=4