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prettypushkova
@prettypushkova
July 2022
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решить систему неравенств
-2х^2 + 3х - 2 < 0
-3(6х - 1) - 2х < х
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sedinalana
Verified answer
1)-2x²+3x-2<0
2x²-3x+2>0
D=9-16=-7<0⇒при любом х выражение больше 0
2)-3(6x-1)-2x<x
-18x+3-2x-x<0
-21x<-3
x>1/7
Ответ x∈(1/7;∞)
2 votes
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Answers & Comments
Verified answer
1)-2x²+3x-2<02x²-3x+2>0
D=9-16=-7<0⇒при любом х выражение больше 0
2)-3(6x-1)-2x<x
-18x+3-2x-x<0
-21x<-3
x>1/7
Ответ x∈(1/7;∞)