Решить систему уравнений x+y=34, log₂x+log₂y=6. Created by trobairitzz. algebra-ru

Решить систему уравнений x+y=34, log₂x+log₂y=6...

July 2022 1 3 Report

Решить систему уравнений
x+y=34,
log₂x+log₂y=6

Answers & Comments

MAXIS95 $x+y=34 \\ log_{2}(xy)=6 \\ x=34-y \\ xy=64 \\ y(34-y)=64 \\ 34y- y^{2}-64=0 \\ y^{2}-34y+64=0 \\ y1=(34+30)/2=32 x1=2 \\ y2=(34-30)/2=2 x2=32 \\$

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trobairitzz July 2022 | 0 Ответы

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