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aliskairiska2
@aliskairiska2
July 2022
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решить уравнение 1) (х+4)^2 = х+6 2) (х-2)(х+2)=5х-10
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gal4enok007
Х^2+8х+18-Х-6=0
Х^2+7х+12=0
Х= -4 Х = -3
Х^2 -4 -5х+10=0
Х^2 -5х +6=0
Х=3 Х=2
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gorshckowashur
Решение:
1)(x+4)^2=x+6
x^2+4*2*x+4^2=x+6
x^2+8x+16=x+6
x^2+8x-x+16-6=0
x^2+7x+10=0
D=(-7)^2-10*4=49-40=9
x1=(-7+3)/2=-2
x2=(-7-3)/2=-5
2)(x-2)(x+2)=5x-10
x^2-2^2=5x-10
x^2-4+10-5x=0
x^2-5x+6=0
D=(-5)^2-6*4=25-24=1
x1=(5+1)/2=3
x2=(5-1)/2=2
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Answers & Comments
Х^2+7х+12=0
Х= -4 Х = -3
Х^2 -4 -5х+10=0
Х^2 -5х +6=0
Х=3 Х=2
1)(x+4)^2=x+6
x^2+4*2*x+4^2=x+6
x^2+8x+16=x+6
x^2+8x-x+16-6=0
x^2+7x+10=0
D=(-7)^2-10*4=49-40=9
x1=(-7+3)/2=-2
x2=(-7-3)/2=-5
2)(x-2)(x+2)=5x-10
x^2-2^2=5x-10
x^2-4+10-5x=0
x^2-5x+6=0
D=(-5)^2-6*4=25-24=1
x1=(5+1)/2=3
x2=(5-1)/2=2