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algoritm211
@algoritm211
July 2022
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Решить уравнение с параметром относительно x
(n^2-5)x + n = n(n-4x)
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MizoriesKun
(n^2-5)x + n = n(n-4x)
(n^2-5)x = n(n-4x)- n
(n^2-5)x = n
²-4xn-n
(n^2-5)x +4xn= n²-n
x*(n²-5+4n)=n²-n
x= n(n-1) / (n²-5+4n)
2 votes
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Answers & Comments
(n^2-5)x = n(n-4x)- n
(n^2-5)x = n²-4xn-n
(n^2-5)x +4xn= n²-n
x*(n²-5+4n)=n²-n
x= n(n-1) / (n²-5+4n)