Решить уравнение:(n+2)!=42n!
(n+2)! = n! * (n+1) * (n+2)
n! * (n+1) * (n+2) = 42 * n!
(n+1) * (n+2) = 42
n^2 + 3n +2 =42
n^2 +3n -40 = 0
Корни: 5 и -8
Ответ: 5
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(n+2)! = n! * (n+1) * (n+2)
n! * (n+1) * (n+2) = 42 * n!
(n+1) * (n+2) = 42
n^2 + 3n +2 =42
n^2 +3n -40 = 0
Корни: 5 и -8
Ответ: 5